Key Takeaways for Particle Model of Matter
1. Density
Formula:
ρ=mVρ=Vm
- Units:
- Density: kg/m³ (kilograms per cubic metre).
- Mass (mm): kg.
- Volume (VV): m³.
Key Rules:
- Solids and liquids are denser than gases (closely packed particles).
- Example: Steel (high density) vs. wood (low density).
Tips:
- Unit conversion:
- 1 g = 0.001 kg; 1 cm³ = 10−610−6 m³.
- E.g., 135 g=0.135 kg135g=0.135kg.
- For irregular solids, use water displacement (volume displaced = object’s volume).
Common Experiment:
- Measure mass with a balance, volume via dimensions (cuboid: Volume=length×width×heightVolume=length×width×height) or displacement.
2. States of Matter
Property | Solid | Liquid | Gas |
---|---|---|---|
Particle Arrangement | Regular, fixed positions | Close, random order | Far apart, random |
Movement | Vibrate in place | Slide past each other | Move freely in all directions |
Density | High | High | Low |
Examples:
- Ice (solid) → Water (liquid) → Steam (gas).
- Why gases are less dense: Particles are spaced out.
Exam Tip:
- Explain floating/sinking using density:
- Cork floats (density < water); stone sinks (density > water).
3. Internal Energy & Changes of State
Internal Energy = Total kinetic + potential energy of particles.
Heating Effects:
- Raises temperature (increases kinetic energy).
- Changes state (increases potential energy).
Changes of State:
Process | Energy Change | Example |
---|---|---|
Melting (solid → liquid) | Energy absorbed | Ice → Water |
Freezing (liquid → solid) | Energy released | Water → Ice |
Evaporation (liquid → gas) | Energy absorbed | Boiling water → Steam |
Condensation (gas → liquid) | Energy released | Dew forming on grass |
Key Rule:
- Temperature remains constant during state changes (energy used to break bonds).
4. Specific Heat Capacity (cc)
Formula:
ΔE=mcΔθΔE=mcΔθ
- Units:
- Energy (ΔEΔE): J (joules).
- Specific heat capacity (cc): J/kg°C.
- Temperature change (ΔθΔθ): °C.
Example:
- Heating 200 kg water from 15°C to 45°C:
ΔE=200×4200×30=25,200,000 J (25.2 MJ)ΔE=200×4200×30=25,200,000J(25.2MJ)
Tips:
- Water’s high cc (4200 J/kg°C) makes it good for heating systems (stores lots of energy).
- Memorise key cc values:
- Aluminium = 880 J/kg°C; Copper = 380 J/kg°C.
5. Specific Latent Heat (LL)
Formula:
E=mLE=mL
- Units:
- Specific latent heat (LL): J/kg.
- Fusion (solid ↔ liquid); Vaporisation (liquid ↔ gas).
Example:
- Melting 8 g of ice (L=334,000 J/kgL=334,000J/kg):
E=0.008×334,000=2672 JE=0.008×334,000=2672J
Exam Trick:
- Steam burns worse than boiling water: Extra energy (LL) released during condensation.
6. Gas Pressure & Particle Model
Key Principles:
- Gas particles move randomly, colliding with container walls (exerting force → pressure).
- Temperature ↑: Particles move faster → collisions harder/more frequent → pressure ↑.
- Boyle’s Law (constant temperature):
P1V1=P2V2P1V1=P2V2- E.g., Halving volume doubles pressure.
Real-World Example:
- Bicycle pump heats up when compressed (work done → energy transferred to particles).
Experiment:
- Tin lid flying off when heated (water evaporates → gas pressure ↑).
7. Practical Tips for Exams
- Unit Conversions: Always convert to kg, m³, or J before calculations.
- Graphs:
- Mass vs. Volume graph gradient = density.
- Flat line on temp-time graph = state change.
- Anomalous Results: Identify outliers in experiments (e.g., wrong material used).
Example Calculation (Density):
- Cuboid: Mass = 173.2 g (0.1732 kg), Volume = 10.1 cm×4.8 cm×1.3 cm=63.1 cm3=6.31×10−5 m310.1cm×4.8cm×1.3cm=63.1cm3=6.31×10−5m3.
ρ=0.17326.31×10−5≈2744 kg/m3ρ=6.31×10−50.1732≈2744kg/m3
Final Revision Checklist:
- Memorise ρ=mVρ=Vm, ΔE=mcΔθΔE=mcΔθ, E=mLE=mL, and P1V1=P2V2P1V1=P2V2.
- Practice unit conversions and graph analysis.
- Understand particle arrangements in solids/liquids/gases.
50 GCSE Questions: Particle Model of Matter
Section 1: Density
- Define density.
- Convert 250 g to kg.
- Calculate the density of a 2 kg object with a volume of 0.5 m³.
- Why does 1 m³ of gas have less mass than 1 m³ of solid?
- Describe an experiment to find the density of an irregularly shaped stone.
Section 2: States of Matter
- List the three states of matter.
- Explain why gases are less dense than solids.
- Draw particle diagrams for solid, liquid, and gas.
- Why can’t liquids be compressed easily?
- Why does ice float on water?
Section 3: Internal Energy
- Define internal energy.
- What happens to internal energy when a substance is heated?
- Why does temperature remain constant during melting?
- Name two changes of state that release energy.
- Explain sublimation with an example.
Section 4: Specific Heat Capacity
- Define specific heat capacity.
- Calculate the energy required to heat 5 kg of water from 20°C to 80°C.
- Why is water used in central heating systems?
- A 3 kg aluminium block is heated by 15°C. Calculate the energy transferred.
- Explain why concrete cools down faster than water.
Section 5: Latent Heat
- Define specific latent heat of fusion.
- Calculate the energy needed to melt 0.5 kg of ice (Lf=334,000 J/kgLf=334,000J/kg).
- Why does steam cause worse burns than boiling water?
- Describe an experiment to measure the latent heat of vaporisation of water.
- A heater supplies 100 kJ to melt 200 g of wax. Calculate LfLf.
Section 6: Gas Pressure & Boyle’s Law
- State Boyle’s Law.
- Explain why gas pressure increases when temperature rises.
- A gas has a volume of 2 m³ at 100 kPa. Calculate its volume at 200 kPa (constant temperature).
- Why does a bicycle pump get hot during use?
- Describe how particle motion causes gas pressure.
Section 7: Experiments & Practicals
- Why is it better to measure a large volume of liquid in density experiments?
- What is the resolution of a balance measuring to 0.1 g?
- How would you measure the thickness of paper using a ruler?
- Identify a source of error in measuring the density of a cuboid.
- Why does a mass vs. volume graph for stones pass through the origin?
Section 8: Calculations & Problem-Solving
- Calculate the density of a cuboid (mass = 173.2 g, dimensions = 10.1 cm × 4.8 cm × 1.3 cm).
- Convert 50 cm³ to m³.
- A rock displaces 30 ml of water. Calculate its volume in m³.
- A gas holder has a volume of 240,000 m³ at 100 kPa. Calculate its volume at 800 kPa.
- A 2 kg metal block absorbs 48,000 J and heats from 20°C to 40°C. Find its specific heat capacity.
Section 9: Applications & Real-World Examples
- Explain why sweating cools the body.
- Why do divers need to exhale while ascending?
- How does a pressure cooker work?
- Why does a tin lid fly off when heated?
- Describe how a refrigerator uses latent heat.
Section 10: Advanced Concepts
- Explain why anomalous results occur in density experiments.
- What does a flat line on a cooling curve represent?
- Why does helium float in air?
- Compare the density of oil and vinegar in salad dressing.
- How does the particle model explain gas expansion?
Detailed Answers
- Density is mass per unit volume: ρ=mVρ=Vm.
- 250 g=0.25 kg250g=0.25kg.
- ρ=20.5=4 kg/m3ρ=0.52=4kg/m3.
- Gas particles are spaced out; fewer particles in 1 m³.
- Submerge the stone in water; measure displaced volume.
- Solid, liquid, gas.
- Gas particles are far apart, less mass per volume.
- Solid: ordered lattice; Liquid: close but mobile; Gas: random, spread out.
- Particles are already close; no space to compress.
- Ice has lower density than water.
- Internal energy = total kinetic + potential energy of particles.
- Internal energy increases (kinetic/potential energy rises).
- Energy breaks bonds; no temperature change.
- Freezing, condensation.
- Solid → gas directly, e.g., dry ice (CO₂).
- Specific heat capacity: Energy needed to raise 1 kg by 1°C.
- ΔE=5×4200×60=1,260,000 JΔE=5×4200×60=1,260,000J.
- High specific heat capacity → stores/releases large energy.
- ΔE=3×880×15=39,600 JΔE=3×880×15=39,600J.
- Lower specific heat capacity → loses energy faster.
- Latent heat of fusion: Energy to melt 1 kg of solid.
- E=0.5×334,000=167,000 JE=0.5×334,000=167,000J.
- Steam releases latent heat when condensing.
- Boil water, measure mass loss & energy input: L=EmL=mE.
- Lf=100,0000.2=500,000 J/kgLf=0.2100,000=500,000J/kg.
- Boyle’s Law: P1V1=P2V2P1V1=P2V2 (constant temperature).
- Faster particles → more collisions → higher pressure.
- V2=100×2200=1 m3V2=200100×2=1m3.
- Work done on gas → increases particle kinetic energy.
- Particles collide with walls, exerting force per unit area.
- Reduces percentage error in measurements.
- The smallest measurable change is 0.1 g.
- Measure 100 sheets, divide total thickness by 100.
- Inconsistent measurements of dimensions.
- Zero mass = zero volume (proportional relationship).
- Convert mass: 173.2 g=0.1732 kg173.2g=0.1732kg. Volume: 10.1×4.8×1.3=63.1 cm3=6.31×10−5 m310.1×4.8×1.3=63.1cm3=6.31×10−5m3. Density: ρ=0.17326.31×10−5≈2744 kg/m3ρ=6.31×10−50.1732≈2744kg/m3.
- 50 cm3=50×10−6=5×10−5 m350cm3=50×10−6=5×10−5m3.
- 30 ml=30 cm3=3×10−5 m330ml=30cm3=3×10−5m3.
- V2=100×240,000800=30,000 m3V2=800100×240,000=30,000m3.
- c=48,0002×20=1200 J/kg°Cc=2×2048,000=1200J/kg°C.
- Sweat evaporates, absorbing latent heat from skin.
- Expanding air in lungs → risk of lung damage.
- High pressure raises boiling point → faster cooking.
- Heating → gas pressure exceeds atmospheric pressure.
- Absorbs latent heat to evaporate coolant, cooling the interior.
- Measurement errors or impurities in the material.
- Change of state (e.g., freezing).
- Helium density < air density.
- Oil (lower density) floats on vinegar.
- Particles spread out → occupy larger volume.
Exam Tip: Practice unit conversions and formula rearrangements! Use ΔE=mcΔθΔE=mcΔθ, E=mLE=mL, and P1V1=P2V2P1V1=P2V2 for calculations.